a rectangular wire of length. 2cm and breadth 1.5 cm is placed at a distance of 25 cm from the concave mirror of focal length 10 cm area of image formed is
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Answered by
3
Answer:
We have,
u = -25cm (object distance)
f = - 10cm. (focal length)
v = ? (image distance)
From the mirror formula,
1/u + 1/v = 1/f
Or, 1/-25 + 1/v = 1/-10
Or, 1/v = 1/-10 + 1/25
Or, 1/v = (-5+2)/50
Or, 1/v = -3/50
Or, v = -50/3
= 16.66 cm
so the image is formed at a distance of 16.66 cm behind the mirror (positive value shows that image is formed behind the mirror).
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Answered by
0
Answer:
4/3=1.333
Explanation:
u=-25cm
f=-10cm
1/f=1/v+1/u
from this v=-50/3cm
linear magnification,m=-2/3
area of image=m²(area of object)
=(2/3)²(2)(1.5)
=4/3=1.33 cm²
=
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