Question

A rectangular wire of length 40 cm and breadth 10 cm is bent in the shape of a square. The side of the square is​

Answer 1

Given: A rectangular wire of length 40cm and breadth 10cm is bent in the shape of a square.

Need to find: What is the side of the square?

Solution: Let's consider that a cm be the length of the square.

As it is given that, a rectangular wire of length 40 cm and breadth 10 cm is bent in the shape of a square. So, the perimeter of the square just be equal to the perimeter of the rectangle.

$\begin{array}{l}\Rightarrow \text{Perimeter of the square = Perimeter of the rectangle} \\ \\ \Rightarrow 4a = 2(l + b) \\ \\ \Rightarrow 4a = 2(40 + 10) \\ \\ \Rightarrow 4a = 2(50) \\ \\ \Rightarrow 4a = 100 \\ \\ \Rightarrow a = \dfrac{100}{4} \\ \\ \Rightarrow \boxed{a = 25}\end{array}$

Hence, the length of the side of the square is 25cm.

Answer 2

$\huge \bf \: ✪Concept :$

• In this question we have to find the side of the square.Here it is given that the length of the rectangular wire is 40 cm and breadth is 10 cm.The rectangular wire is bent in shape of a square.

Solution:

$\rm \: we \: know \: that$

$\sf \: length \: = 40cm \\ \sf breadth = 10 \: cm$

Perimeter of rectangle=

$\bf \: 2( l+b) =2(40+20) cm=120 cm$

$\sf \: Perimeter \: of \: square=perimeter \: of \: rectangle=120cm$

$\rm \: to \: find \: the \: side \: of \: the \: square \: \rightarrow$

$\frac{120}{4} \implies \: 30$

So,the side of the square is 30 cm.

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