Question

A rectangular wire of length 40 cm and breadth 10 cm is bent in the shape of a square. The side of the square is​​

Answer 1

A rectangular wire of length 40 cm and breadth 10 cm is bent in the shape of a square. The side of the square is

Answer 2

Answer:

Given: A rectangular wire of length 40cm and breadth 10cm is bent in the shape of a square.

Need to find: What is the side of the square?

Solution: Let's consider that a cm be the length of the square.

As it is given that, a rectangular wire of length 40 cm and breadth 10 cm is bent in the shape of a square. So, the perimeter of the square just be equal to the perimeter of the rectangle.

\begin{gathered}\begin{array}{l}\Rightarrow \text{Perimeter of the square = Perimeter of the rectangle} \\ \\ \Rightarrow 4a = 2(l + b) \\ \\ \Rightarrow 4a = 2(40 + 10) \\ \\ \Rightarrow 4a = 2(50) \\ \\ \Rightarrow 4a = 100 \\ \\ \Rightarrow a = \dfrac{100}{4} \\ \\ \Rightarrow \boxed{a = 25}\end{array}\end{gathered}

⇒Perimeter of the square = Perimeter of the rectangle

⇒4a=2(l+b)

⇒4a=2(40+10)

⇒4a=2(50)

⇒4a=100

⇒a=

4

100

⇒

a=25

Hence, the length of the side of the square is 25cm.