Question

A rectangular wire of length 40 cm and breadth 20 cm is bent in the shape of a square. The side of the square is

20 cm

30 cm

40 cm

10 cm

​

Answer 1

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Perimeter of the rectangle = 2(Length + Breadth)

= 2(40 + 20) cm = 2(60) cm = 120 cm.

Thus the perimeter of the rectangle is 120 cm. If it is rebent into a square, it's perimeter will be also 120 cm as the length of wire is 120 cm. Therefore,

Perimeter of square = 4 × side

= 120 = 4 × side

= side = 120/4 = 30 cm.

Thus the side of the square is 30 cm.

Answer 2

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Solution:-

perimeter =?

$= 2 \times (l + b)$

$= 2 \times (40 + 20)$

$= 2 \times 60 = 120$

side=perimeter÷4

$= 120 \div 4 = 30$

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