Question

A rectangular wire of length 40cm and breadth 20cm is bent in the shape of a square. The side of the square is?​

Answer 1

Answer:

The perimeter of rectangular wire = 2(40+20)= 120cm

the side of square = 120/4 = 30

Answer 2

Question:-

A rectangular wire of length 40cm and breadth 20cm is bent in the shape of a square. The side of the square is?

Answer:-

• The side of square is 30 cm.

To find:-

• Side of square

Solution:-

• Length of Rectangle (l) = 40 cm
• Breadth of rectangle (b) = 20 cm

As we know,

$\mathfrak{ \green{ \huge{perimeter = 2(l + b)}}}$

According to question,

$\large{ \tt : \implies \: \: \: \: perimeter = 2(40 + 20)}$

$\large{ \tt : \implies \: \: \: \: perimeter = 2 \times 60}$

$\large{ \tt : \implies \: \: \: \: perimeter = 120 \: cm}$

• The perimeter of rectangle is 120 cm.
• The same rectangular wire is bent in the shape of square

Thus,

• Perimeter of rectangle = Perimeter of square
• Perimeter of square = 120 cm
• Side of square = x

As we know,

$\mathfrak{ \purple{ \huge{ perimeter = 4 \times side}}}$

According to question, $\large{ \tt : \implies \: \: \: \: 4 \times x = 120}$

$\large{ \tt : \implies \: \: \: \: x = \frac{120}{4} }$

$\large{ \tt : \implies \: \: \: \: x = 30}$

Hence,

• The side of square is 30 cm.