Question

A rectangular wooden block has mass 5kg .The length ,breadth and height of the wooden block are 50cm ,25cm and 10 cm respectively. Find the pressure on the table top when wooden block is kept with surface measuring
a.50cm * 25cm on the table
b.10cm * 50cm on the table

Answer 1

Solution :

Pressure = Force / Area

Force = Mass × g

g = 9.8 N

Force = 9.8 × 5

Force = 49 N

Pressure on the table when wooden block is kept with surface measuring 50 cm × 25 cm,

Here Force = 49 N

area = (50/100) metre × (25/100)metre

Pressure = Force/Area

49 ÷ {(50/100)×(25/100)}

(49 × 100 × 1000) / 50 × 25

= 392 N/m^2

Pressure on the table top when wooden block is kept with measuring 10 cm × 50 cm,

Here Force = 49 N

Area = (10/100)metre × (50/100)metre

Pressure = Force/Area

Pressure = 49 ÷ {(10/100) ×(50/100)}

Pressure = (49 × 100 × 100) / (10 × 50)

Pressure = 980 N/m^2