A Rectangular Wooden Piece Weighs 25 N.If It Is Played In Such Way That Its 25 Cm Length And 10 Cm Width Are In Contact With A Surface,Whay Will Be The Pressure Exerted By It On The Surface
Answers
Answered by
11
Answer:
pressure= force/area
Explanation:
so. if the surface is in contact with the side having 25 cm length and 10 cm Breadth . then,
area => 25cm×10cm
= 250cm²
now, we know that
weight=mg(mass × gravitational acceleration)
and also F(force)=mass× acceleration
so the magnitude of force is given as 25 N or 25 kg m/ s²
as the area in cm² so covert force into kg cm / s²
25 kg 100 cm / s²
= 2500 kg cm /s²
now,
pressure = (2500kg cm/ s²)/(250 cm²)
= 10 kg / cm s²
further convert your ans in the unit which you want to
:)
Similar questions