Question

a rectangular Yard contains two flower beds in a shape of congruent isosceles right triangle the remaining portion is the head of trapezoidal Shape whose parallel sides have length 15 M and 25 m what fraction of the yard is occupied by the flower bed​

Answer 1

ach triangle has leg length $\frac 12 \cdot (25 - 15) = 5$ meters and area $\frac 12 \cdot 5^2 = \frac {25}{2}$ square meters. Thus the flower beds have a total area of 25 square meters. The entire yard has length 25 m and width 5 m, so its area is 125 square meters. The fraction of the yard occupied by the flower beds is $\frac {25}{125} = \boxed{\frac15}$. The answer is $\mathrm{(C)}$.