Question

a rectanguler room measuring 3.4m x 2.5mx2.6 the walls
of the room ore painted, find the cost of painting the four
walls of the room of the cost of 22 super.bermater​

Answer 1

Given -

Length = 3.4 m

Breadth = 2.5 m

Height = 2.6 m

To find -

The cost of painting the four walls of the room.

Solution -

By using the formula of surface area of rectangle where -

l × b × h = surface area of rectangle

L = Length

B = Breadth

H = Height

Applying the formula -

→ Surface area of the room = 3.4 × 2.5 × 2.6 m

→ SA of room = 22.1 m²

Cost of painting the walls = Area of walls × Cost given

Cost of painting = 22.1 × 22 = ₹ 486.2

$\therefore$ The area of walls are 22.1m² and cost of painting the walls is ₹486.2

______________________________________

Answer 2

★GIVEN★

• a rectanguler room measuring 3.4m × 2.5m × 2.6 the walls of the room are painted.
• Cost of painting = ₹22 per metre square.

★TO FIND★

Cost of painting of four walls of the room.

★SOLUTION★

We know that surface area of rectangle is,

$\large{\underline{\boxed{\sf{l\times\:b\times\:h}}}}$

where,

• l = length
• b = breath
• h = height

Now,

• l = 3.4m
• b = 2.5m
• h = 2.6

According to the question,

$\large\implies{\sf{Surface\:Area=l\times\:b\times\:h}}$

Putting the values,

$\large\implies{\sf{Surface\:Area=3.4\times2.5\times2.6}}$

$\large\implies{\sf{Surface\:Area=22.1\:{m}^{2}}}$

$\large{\underline{\boxed{\therefore{\sf{Surface\:Area\:of\:room=22.1\:{m}^{2}.}}}}}$

★Now the cost of painting the four walls★

$\large\implies{\sf{Cost=₹(22.1\times22)}}$

$\large{\underline{\boxed{\therefore{\sf{₹486.2.}}}}}$

$\large{\pink{\underline{\boxed{\therefore{\bf{Cost\:of\:painting\:four\:walls\:is\:₹486.2.}}}}}}$