Question

A rectanhular field is 112m long and 100m wide. Two cross roads each of width 5m are constructed at the centre of this field, one is parallel to the length of the field and the other is parallel to the breadth of the field, Find:
(a) area of the two cross roads.
(b) area of remaining field.
(c) cost of laying grass in the remaining field at the rate of ₹2 per m².
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Answer 1

Step-by-step explanation:

(a) Area of the field = l×b = 112×100 = 11,200 m²

Width of crossroad = 5m

Area of crossroad parallel to length of the field = 5×112 = 560 m²

Area of crossroad parallel to the width of the field = 5×100 = 500 m²

Area of the meeting point of the 2 roads = 5×5 = 25 m²

Area of crossroad = Area of 2 crossroads - Area of junction

Area of crossroad = (560+500)-25 = 1,035 m²

(b) Area of remaining field = Area of field - Area of crossroad

Area of remaining field = 11200-1035 = 10,165 m²

(c) Cost per m² = ₹ 2

Cost for 10165 m² = 10165×2 = ₹ 20,330

Answer 2

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