Question

A rectengulas peace of papes 11 CM, 4cm
is folded without overlapping
to make cylinder of hight 4 cm - find the
Volume of the
cyliendis​

Answer 1

Perimeter of the base of Cylinder = 11 cm

or, 2πr = 11

2 × 22/7 × r = 11

44r = 77

r = 7/4 cm

Volume = πr²h

= 22/7 × 7/4 × 7/4 × 4

= 22 × 7/4

= 38.5 cm³

Answer 2

Answer:

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