A rectengulas peace of papes 11 CM, 4cm
is folded without overlapping
to make cylinder of hight 4 cm - find the
Volume of the
cyliendis
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Perimeter of the base of Cylinder = 11 cm
or, 2πr = 11
2 × 22/7 × r = 11
44r = 77
r = 7/4 cm
Volume = πr²h
= 22/7 × 7/4 × 7/4 × 4
= 22 × 7/4
= 38.5 cm³
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