Question

a rectnagular field is 40m long and 30m broad , find lengh of its diagonal??

Answer 1

Answer:

The length=40m

width=30m

Let the diagonal=x

clearly the diagonal acts as a hypotenuse of triangle whose base is 40m and height is 30m

applying PGT

${x}^{2} = {30}^{2} + {40}^{2}$

${x}^{2} = 900 + 1600$

${x}^{2} = 2500$

$x = \sqrt{2500}$

$x = 50$

Therefore diagonal =50m

Answer 2

Given

• In a rectangular field
• Length = 40 m
• Breadth = 30 m

To find

• Length of diagonal

Solution

• ΔACD is right angled triangle at C

By Pythagoras theorem :-

• AD² = AC² + DC²
• AD² = 30² + 40²
• AD² = 900 + 1600
• AD² = 2500
• AD = √2500
• AD = 50

∴ The length of AD = 50 m