Math, asked by kshitijrampurkar77, 10 months ago

A red, a blue and a green dice are thrown at the same time, display all the possibile outcomes in a suitable way, find the probability of obtaining :

a) a total of 18 on a three dice
b) a total of 4 on a three dice
C) a total of 10
D) total of 15
E) total of 7
F) the same number on each dice
.
.

guys please explain me this question step by step tomorrow i have to solve this type of problem please guys it will be help ful if u all helped me ​

Answers

Answered by BrainlyEmpire
8

Answer:

Hello mate..

Step-by-step explanation:

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Probability for Rolling Three Dice

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Probability for rolling three dice with the six sided dots such as 1, 2, 3, 4, 5 and 6 dots in each (three) dies.

When three dice are thrown simultaneously/randomly, thus number of event can be 63 = (6 × 6 × 6) = 216 because each die has 1 to 6 number on its faces.

Worked-out problems involving probability for rolling three dice:

1. Three dice are thrown together. Find the probability of:

(i) getting a total of 5

(ii) getting a total of atmost 5

(iii) getting a total of at least 5.

(iv) getting a total of 6.

(v) getting a total of atmost 6.

(vi) getting a total of at least 6.

Solution:

Three different dice are thrown at the same time.

Therefore, total number of possible outcomes will be 63 = (6 × 6 × 6) = 216.

(i) getting a total of 5:

Number of events of getting a total of 5 = 6

i.e. (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1), (2, 1, 2) and (1, 2, 2)

Therefore, probability of getting a total of 5

Number of favorable outcomes

P(E1) = Total number of possible outcome

= 6/216

= 1/36

(ii) getting a total of atmost 5:

Number of events of getting a total of atmost 5 = 10

i.e. (1, 1, 1), (1, 1, 2), (1, 2, 1), (2, 1, 1), (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1) and (1, 2, 2).

Therefore, probability of getting a total of atmost 5

Number of favorable outcomes

P(E2) = Total number of possible outcome

= 10/216

= 5/108

(iii) getting a total of at least 5:

Number of events of getting a total of less than 5 = 4

i.e. (1, 1, 1), (1, 1, 2), (1, 2, 1) and (2, 1, 1).

Therefore, probability of getting a total of less than 5

Number of favorable outcomes

P(E3) = Total number of possible outcome

= 4/216

= 1/54

Therefore, probability of getting a total of at least 5 = 1 - P(getting a total of less than 5)

= 1 - 1/54

= (54 - 1)/54

= 53/54

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Answered by deodeoprakash
9

Step-by-step explanation:

explain in the image please see the image

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