Question

A red car, travelling at 2 m/s, hit a blue car at rest. If the cars have equal masses of 2 kg, and the collision is elastic, what will be the speed of the red car immediately after the impact?

Answer 1

because momentum is conserved and initial momentum is equal to the final momentum so, velocity. of blue car will be 2 m/s

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Velocity\:of\:red\:car\:after\:collision=1\:m/s}}}$

$</p><p></p><p>\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}</p><p></p><p></p><p>$

$\green{\underline \bold{Given :}}$

$\tt : \implies Red \: car \: mass( m_{1}) = 2 \: kg$

$\tt: \implies Velocity \: of \: car( v_{1}) =2 \: m/s$

$\tt : \implies Blue \: car \: mass( m_{2}) = 2 \: kg$

$\red{\underline \bold{To \: Find :}}$

$\tt: \implies Velocity\:of\:red\:car\:after\:collision( v_{c}) =?$

• Given Question

$\tt \circ \: Velocity \: of \: m_{2} = 0 \: m/s$

$\bold{As \: we \: know \: that}$

$\tt: \implies m_{1} v_{1} + m_{ 2 } v_{2} = ( m_{1} + m_{2}) v_{c}$

$\tt: \implies 2 \times 2 + 2\times 0 = (2+2) v_{c}$

$\tt: \implies 4 + 0 = 4 \times v_{c}$

$\tt: \implies v_{c} = \frac{4}{4}$

$\green{\tt: \implies v_{c} = 1 \: m/s}$

$\green{\tt \therefore velocity\:of\:red\:car \:after\:collision\: is \: 1 \: m/s}$