A red light and blue light enter a rectangular glass
block normal to its surface at the same time. Strictly
speaking, after passing through the block, which
pulse exits first?
Answers
in this case I think the blue light
Answer:
Because both lights travel at the same speed in air and will do so in glass as well, they will emerge simultaneously. As a result, both will emerge from the slab simultaneously.
As the wavelength of light lowers, there is more refraction. Light with shorter wavelengths (violet and blue) is slowed more and bends more than light with longer wavelengths because of this (orange and red).
Explanation:
Red light has a slightly lower index of refraction than blue light for all other media besides vacuum. This indicates that the red light deviates from its original direction less than the blue light does when light travels from vacuum into glass. Additionally, the red light again deviates less than the blue light as it escapes from the glass towards vacuum. The red and blue rays will emerge from the glass travelling perpendicular to one another but displaced laterally from one another if the two transparent surfaces are equivalent to each other.
The light bends more in the glass at slower speeds. Since the colours are dispersed in many directions, we refer to this effect as dispersion. Blue light penetrates glass from the air at a sharper angle than red light because it travels slightly slower in glass than red light.
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