A reduction of 10% in the price of an article enables a dealer to purchase 25 articles more for Rs 4500. What is the original price of the article?
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53
Let original price=x
10% Of x= x* 10/100
= X/10
Reduction of 10% = X-X/10
=10x-x/10
=9x/10
no.of products bought initially=Y
before reduction In price=> XY=4500
after reduction =9x/10(Y+25)=4500
=9xy/10+225x/10=4500
9*4500+225x/10=4500(by taking lcm)
40500+225x=4500*10
40500+225x=45000
225x=45000-40500
225x= 4500
X= 4500/225
X= 900/45
X= 20
original cost of the article is Rs20.
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10% Of x= x* 10/100
= X/10
Reduction of 10% = X-X/10
=10x-x/10
=9x/10
no.of products bought initially=Y
before reduction In price=> XY=4500
after reduction =9x/10(Y+25)=4500
=9xy/10+225x/10=4500
9*4500+225x/10=4500(by taking lcm)
40500+225x=4500*10
40500+225x=45000
225x=45000-40500
225x= 4500
X= 4500/225
X= 900/45
X= 20
original cost of the article is Rs20.
if helped plz mark brainliest ans.
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