Question

A reduction of 20% in the price of sugar enables Mrs Shah to buy an extra 3 kg of it for rupees 360 find the original rate and the reduced rate per kg.

Answer 1

The solution is based on the concept of inverse proportion. Reduced price in this case will be 360/3 which is 60 rupees.

 Consider X as the original price. Thus, 0.8X = 60

Thus, X becomes 75. Therefore, the original price of the sugar will be Rupees 75 which will enable Mrs. Shah to buy more of it when price is reduced by 20%.

Answer 2

Answer:

Original Price is Rs. 30 and Reduced Price is Rs. 24

Step-by-step explanation:

Let Rs. x be the original Price of sugar per kg.

Rs. y be the original quantity of sugar per kg.

According to the question,

xy = 360

$(x-\frac{20}{100}x)(y+3)=360$

$xy-\frac{20}{100}xy+3x-\frac{20\times3}{100}x=360$

$360-\frac{1}{5}\times360+3x-\frac{3}{5}x=360$

$-72+\frac{12x}{5}=0$

12x/5 = 72

x = 6 × 5

x = 30

Reduced Price of Sugar = 30 - 20/100 × 30 = 30 - 6 = Rs. 24

Therefore, Original Price is Rs. 30 and Reduced Price is Rs. 24