Math, asked by kruti1072, 3 months ago

A reduction of 33% in the price of oranges would enable a purchaser
to obtain 8 more for a rupee. What was the price in paise, per orange,
before the reduction?​

Answers

Answered by queendaro
2

Answer:

Let x be number of oranges that can be bought with one rupee.

Then price of an orange is 1/x rs.

Now final price of orange becomes 2/(3x) rs.(as one third of price is reduced)

Then number of oranges now bought per rupee is 3x/2.

Thus extra oranges bought now is 3x/2-x=x/2.

Given x/2=8 =>x=16.

Thus price of each orange is 1/16 rupees or 6.25 paise before reduction of price.

Happy solving….

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