A reduction of20% in the price of sugar enables Mrs. Jones to buy an extra 5 kg of it for $ 320.
Find:
(i) the original rate, and
(ii) the reduced rate per kg.
Answers
Answer:
hiii
your answer is here !
Step-by-step explanation:
Let the original rate be $ x per kg.
Reduced rate = (80% of $ x) per kg
= $ (x × 80/100) per kg
Quantity of sugar for $ 320 at original rate = 320/x kg
Quantity of sugar for $ 320 at the new rate = 320/(4x/5) kg
= (320 × 5)/4x kg
= 400/x kg.
Therefore, (400/x) - (320/x) = 5
⇔ 5x = (400 - 300)
⇔ 5x = 80
⇔ x = 16
(i) Original rate = $ 16 per kg
(ii) Reduced rate = (4/5 × 16) per kg
= $ 64/5 per kg
= $ 12.80 per kg.
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Answer:
hlo
your answer is here !
Step-by-step explanation:
Let the original rate be $ x per kg.
Reduced rate = (80% of $ x) per kg
= $ (x × 80/100) per kg
Quantity of sugar for $ 320 at original rate = 320/x kg
Quantity of sugar for $ 320 at the new rate = 320/(4x/5) kg
= (320 × 5)/4x kg
= 400/x kg.
Therefore, (400/x) - (320/x) = 5
⇔ 5x = (400 - 300)
⇔ 5x = 80
⇔ x = 16
(i) Original rate = $ 16 per kg
(ii) Reduced rate = (4/5 × 16) per kg
= $ 64/5 per kg
= $ 12.80 per kg.
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