Question

A refrigerator and a washing machine were sold for ` 12000 each. The
shopkeeper made a loss of 25 % on the refrigerator and a profit of 20 % on
the washing machine. Find the gain or loss % in the whole transaction.

Answer 1

Step-by-step explanation:

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. y

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000 + y

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000 + y= 15000 + 10000

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000 + y= 15000 + 10000= Rs. 25,000

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000 + y= 15000 + 10000= Rs. 25,000And total selling price of both items

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000 + y= 15000 + 10000= Rs. 25,000And total selling price of both items= 12000 + 12000

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000 + y= 15000 + 10000= Rs. 25,000And total selling price of both items= 12000 + 12000= Rs. 24000

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000 + y= 15000 + 10000= Rs. 25,000And total selling price of both items= 12000 + 12000= Rs. 24000Loss = 25000 - 24000

Step-by-step explanation:Let the cost price of refrigerator be Rs. x and that of a camera be Rs. ySince refrigerator was sold for as sold for Rs. 12000 at a loss of 20%.12000 = x(100−20100)= > x = 12000×10080=15,000 and a camera was sold for Rs. 12000 at a profit of 20%.12000 = y(12000×100120)Y = 12000×100120= 10000 + y= 15000 + 10000= Rs. 25,000And total selling price of both items= 12000 + 12000= Rs. 24000Loss = 25000 - 24000=Rs.1000