Question

A refrigerator converts 100g of water at 20 Celsius to ice at -10 Celsius in 35 minutes. calculate the average rate of heat extraction in terms of watt​

Answer 1

Answer:

RATE OF HEAT EXTRACTION = Q/t

specific heat. of water= C = 4.1 j/g

so total heat = Q = nCΔT = 100×4.1×(30) = 12300 j

so Rate = 12300/35×60 = 5.86 j/s

Hope it helps..