Question

A refrigerator is designed to release 750 calories of heat per second. IF the range of its operation is 5 degree Celsius to 25 Celsius then its power is

Answer 1

Answer: The power is 53.95 W

Explanation:

Where,

Tc = Low temperature = 5°C = 278 K

Th = High temperature = 25°C = 298 K

On substituting the values, we get,

COP = 278/(298 - 278)

∴ COP = 278/20

Now, the power is given by the formula:

COP = (Desired effect)/Input

Desired effect = 750 calories of heat per  second = 750 J

On substituting the values, we get,

278/20 = 750/Input

∴ Input = 53.95 J/s = 53.95 W = Power consumed by the refrigerator