Question

A refrigerator operates on average for 12 hours a day. if the power rating of the fridge is 600 watt .How much electrical energy does the fridge use in one week in joule and kilowatt hour

Answer 1

E=P×T

$energy = 12 \times 600$

E = 7200 JOULES

E =7200/1000KWH

E= 7.2 KWH

Answer 2

Answer:

Time of Usage Per Day = 12 Hours

Power Rating = 600 W

Electrical Energy in 1 week = ?

Power Rating = 600 W which can be written as 0.6 kW

We know that the fridge is operated 12 hours a day.

⇒ 0.6 × 12 Hours / day = 7.2 kWh / day

Therefore in 1 week, the power consumed would be:

⇒ 7.2 kWh × 7 = 50.4 kWh

We know that 1 kWh = 3.6 × 10⁶ J

Therefore 7.2 kWh = 7.2 × 3.6 × 10⁶ J / day

7.2 kWh = 25.92 × 10⁶ J / day

Since it is used for 7 days, we multiply by 7 and we get,

50.4 kWh = 25.92 × 7 × 10⁶ J

50.4 kWh = 181.44 × 10⁶ J

This is the required answer !!

Hope it helped !!

Thanks !!