Question

a refrigerator was sold at a gain of 10%. had it been sold for rupees 325 more, the gain would have been 12%. find CP of refrigerator .


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Answer 1

Answer:

The cost price of refrigerator is Rs 16250 .

Step-by-step explanation:

Given as :

The selling price of refrigerator = Rs x

Let The cost price = Rs y

The gain percentage = 10%

Or, gain % = $\dfrac{selling price - cost price}{cost price}$

or, 10% = $\dfrac{x-y}{y}$

Or, $\dfrac{10}{100}$ = $\dfrac{x}{y}$ - 1

or, $\dfrac{x}{y}$ = $\dfrac{10}{100}$ + 1

or, $\dfrac{x}{y}$ = $\dfrac{110}{100}$            .....1

i.e  x = 1.1 y

Again

If selling price is rs 325 omre

i.e Selling price = Rs (x + 325)

Cost price = Rs y

Gain % = 12 %

i.e gain % = $\dfrac{selling price - cost price}{cost price}$

Or, 12 % = $\dfrac{x + 325 - y}{y}$.

or, $\dfrac{12}{100}$ = $\dfrac{x+325}{y}$ - 1

or, $\dfrac{x+325}{y}$ = $\dfrac{112}{100}$

Or, $\dfrac{x}{y}$ + $\dfrac{325}{y}$ = 1.12

Or, 1.1 + $\dfrac{325}{y}$ = 1.12                   ......(from eq1 )

or, $\dfrac{325}{y}$ = 1.12 - 1.1

Or, $\dfrac{325}{y}$ = 0.02

∴  y = $\dfrac{325}{0.02}$

i.e  y = Rs 16250

So, The cost price of refrigerator = y = Rs 16250

Hence, The cost price of refrigerator is Rs 16250 . Answer

Answer 2

Hence, The cost price of refrigerator is Rs 16250 . Answer

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