Physics, asked by seema2122, 9 months ago

A refrigerator, whose coefficient of performance k is 5, extracts heat from the cooling compartment at the rate of 250 j per cycle. How much work per cycle is required to operate the refrigerator cycle ?

Answers

Answered by killer365

0

Answer:

I guess the answer is 50

Explanation:

using the equation

B (coefficient of performance) =Q2/W

5=250/W

W=250/5

=50

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