Question

a region of space contains electric field of magnitude 1325 N/C. A wire frame forming a square 0.27 on a side is placed in the region, oriented so that the perpendicular to the plane of the square makes an angle 48° with the field what is the magnitude of electric flux through the frame

Answer 1

Answer:

The answer will be  64.6 N/C m^2

Explanation:

According to the problem the electric field is given  let take that as E

Now the wire is creating the square in a way that the side of the square is  0.27

Now the square has made an angle with the electric field.

Therefore,

the electric flux = E . A = EA cos θ = 1325 x (0.27 x 0.27) x cos 48°

                         = 64.6 N/C m^2