Question

A regular die is thrown. The probability of getting the number 4 in the first throw and 5 in the second throw is:

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

As we already know that there are 6 outcomes in this case. The outcomes are {1,2,3,4,5,6}

Probability of getting 4 in the first throw

= ( No. of favorable cases) / (Total no. of cases)

=1/6

Similarly,

Probability of getting 5 in the second throw = 1/6

Since probability of getting a number is independent of one another, both the probabilities are multiplied.

P( 4 in first throw) * P( 5 in second throw) = 1/6 * 1/6 = 1/36