A regular field is 20m long and 14m wide there is path of equal width all around it .having an area 111sq.m find the width of the path
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Correct Question - A rectangular field is 20m long and 14m wide. There is a path of equal width all around it.having an area 111sq.m find the width of the path
Solution :-
Assumption,
Width = p m
Also
Length = 20 + 2p m
Width of path = 14 + 2p m
Situation,
As we know that
Area of rectangular path = L × B
= (20 + 2p)(14 + 2p)
= 4p² + 68p + 280
Given,
Area of path = 111 m²
So,
4p² + 68p + 280 = 111 m²
Subtract 280 from LHS, we get,
4p² + 68p + 280 - 280 = 111 m²
4p² + 68p = 111 m²
4p² + 68p - 111 = 0
4p² + 74p - 6p - 111 = 0
2p(2p + 37) - 3(2p + 37) = 0
(2p + 37)(2p - 3) = 0
p = -37/2, 3/2 = 0
p = -18.5, 1.5 (Negative value is not applicable)
p = 1.5 m
Therefore,
Width of path = 1.5 m
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