A regular hexagon has a side of 4 cm, find its area
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A regular hexagon contains 6 equilateral triangles of side length 4 cm
now,
area of one equilateral triangle = √3 a²/4
= √3 (4)²/4
= 4√3 cm²
so, area of hexagon = 6 ×4√3 = 24√3 cm²
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________________________
A regular hexagon contains 6 equilateral triangles of side length 4 cm
now,
area of one equilateral triangle = √3 a²/4
= √3 (4)²/4
= 4√3 cm²
so, area of hexagon = 6 ×4√3 = 24√3 cm²
HOPE , IT HELPS .
FOLLOW ME . ✌
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