A regular hexagon inscribed in a circle. if the area of hexagon is 24 root 3 cm square, find the area of the circle.
Answers
Answered by
17
Join all corners of hexagon with centre of cirlce and u will see 6 equilateral traingles there!!
Let the radius of circle be "r" which is same as side of equilateral traingles!!
Since there are 6 equilateral triangle forming that hexagon!
6×[(root3)/4]a.a=24root3
a=4
Area of circle = πa.a
=16π
Let the radius of circle be "r" which is same as side of equilateral traingles!!
Since there are 6 equilateral triangle forming that hexagon!
6×[(root3)/4]a.a=24root3
a=4
Area of circle = πa.a
=16π
Answered by
6
Answer:
Step-by-step explanation:
Now for this,
We have ,the area of hexagon =24root3 cm square.
A.T.F(According to formula)
We have,
3root3/2a square = 24root3 cm square
Hence, by calculating,
a square =16.
So,a=4.
So,we have radius = 4cm.
Now ,according to question...
Area of circle =pie r square.
Now putting all values..
We get,
3.14×4×4=50.24cm square....
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