a regular hexagon is inscribed in a circle and a smaller circle is inscribed in the hexagon formed by joining its diagonals . If x is the ratio of the area of the bigger circle to that of the smaller circle find x
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Answer:
Step-by-step explanation:
In **Δ OPE**
**OP=OE=r**
So ∠ OPE=∠ OEP= p ( say)
∠ POE =360/6=60
Then p+p+60=180, p=60
Thus ∠ OPE=∠ OEP=∠POE=60
Therefore **Δ OPE is an equilateral triangle**
So side PE=x=r=10 cm
Thus the perimeter of the hexagonal ABCDEP
**=6*10=60 cm**
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60 cm
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