Question

A regular hexagon of side 10 cm has a charge 5 microcoloumb at each of its vertices. Calculate the potential at the centre of the hexagon.​

Answer 1

Answer:

Let O be the centre of the hexagon

It follows that the point O, when joined to the ends of a side of the hexagon forms an equilateral triangle.

∴AO=BO=CO=DO=EO=FO=10cm=0.1 m

Since at each comer of the hexagon, a charge of 5pc i.e., 5×10−6C is placed, total electric potential at point o due to the charges at the six comers,

V=6×(

4π∈

0

1

×

r

q

)

=6×9×10

9

×

0.1

5×10

−6

=2.7×10

6

V.

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Answer 2

Explanation:

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