Question

a regular octagon is inscribed in aa circle .the angle that each side of the octagon subtend at the centre​

Answer 1

Answer:

ABCDEFGH is a regular octagon. So AB=BC=….. =HA

There are 8 equal angles AOB, BOC,…, HOA formed and AOB = 360/8 = 45 deg

So in triangle AOB, sum of angles OAB and OBA is (180-45)=135 deg

Since side OA=OB

Angle OAB= Angle OBA = 135/2 deg

And (angle OAB) : (angle AOB) is

(135/2) / 45 i.e. 1.5 or 3:2 Ans

Answer 2

Answer:

ABCDEFGH is a regular octagon. So AB=BC=….. =HA

There are 8 equal angles AOB, BOC,…, HOA formed and AOB = 360/8 = 45 deg

So in triangle AOB, sum of angles OAB and OBA is (180-45)=135 deg

Since side OA=OB

Angle OAB= Angle OBA = 135/2 deg

And (angle OAB) : (angle AOB) is

(135/2) / 45 i.e. 1.5 or 3:2 Ans

Explanation: