Question

A relation aRb => a ≤ b is​

Answer 1

Answer:

Answer

R is not reflexive, if −a is any negative real number, then ∣−a∣>−a so that −a is not in R−a.

R is not symmetric.

Consider the real numbers a=−2 and b=3.

Then, aRb as ∣−2∣<3.

But b not in Ra as ∣3∣≤−2.

R is transitive: let a,b,c be three real numbers such that ∣a∣≤b and ∣b∣≤c.

But ∣a∣≤b⇒b≥0, and so ∣b∣≤c⇒b≤c.

So, it follows ∣a∣≤c.