Question

A relation f is defined by f(x)=x2-2 where x€{-2,-1,0,3} list the elements of f and is f is a function​

Answer 1

Function

Given :- f(x) = x² - 2

x ∈ { -2, -1, 0, 3 }

For finding the elements of f, we need to substitute the values of x in the given function or f(x).

1. For x = - 2

         f(- 2) = (- 2)² - 2

                  = 4 - 2

                  = 2

    2.  For x = - 1

         f(- 1) = (- 1)² - 2

                 = 1 - 2

                 = - 1

    3.  For x = 0

         f(0) = (0)² - 2

                = 0 - 2

                = - 2

 

    4.  For x = 3

         f(3) = (3)² - 2

              = 9 - 2

              = 7

∴ So, f = { 2, -1, -2, 7 }

Here,

         - 2 -------------------------------> 2

         - 1 -------------------------------> - 1

          0 -------------------------------> - 2

          3 -------------------------------> 7

Now, a relation is a function only when every element of the first set has an unique image in the second set.

Above, we can see that for every value of x, there exists a unique value y.

∴ The above relation is a function.

Answer 2

Answer:

here u go pal

Step-by-step explanation:

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