A relation R defined in the set N of natural numbers as R = {(a,b) : |a-b| is even } , is an equivalence relation. write the set of numbers which are related with no 1 according to given relation.
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Given A={1,2,3,4,5} and R={(a,b):∣a−b∣is even}
To prove that it is equivalent relation we need to prove that R is reflexive, symmetric and transitive.
(i) Reflexive:
Let aϵA
then ∣a−a∣=0 is an even number
∴(a,a)ϵR,∀aϵA
∴R is reflexive
(ii) Symmetric
Let a,bϵA
∀(a,b)ϵR⇒∣a−b∣ is even
⇒∣−(b−a)∣ is even
⇒∣b−a∣ is even
⇒∣b−a∣ϵR
or (b,a)ϵR
∴R is symmetric
(iii) Transitive
Let a,b,cϵA
∀(a,b)ϵR and (b,c)ϵR
we have ∣a−b∣ is even and ∣b−c∣ is even
⇒a−b is even and b−c is even
⇒a−b is even and b−c is even
⇒(a−b)+(b−c) is even
⇒a−c is even
⇒∣a−c∣ is even ⇒(a,c)ϵR∴R is transitive
∴R is an equivalence relation.
Step-by-step explanation:
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