Question

A Relation R is defined from the set of integers to the set of real numbers as (x,y)=R if x²+y² = 16, then the domain of R is:

a) (0,4,4)
b) (0,-4,4)
c) (0,-4,-4)
d) (0,4,-4)​

Answer 1

the answer is b option

Subtract x^2 from both sides of the equation

y^2=16-x^2

square rootof y

y=sqrt of 16-x^2

y=(4+x)(4-x)

x=-4,4

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

A Relation R is defined from the set of integers to the set of real numbers as (x,y) ∈ R if x²+y² = 16, then the domain of R is:

a) { 0,4,4 }

b) { 0, - 4,4 }

c) { 0,-4,-4 }

d) { 0,4,-4 }

EVALUATION

Here the Relation R is defined from the set of integers to the set of real numbers as (x,y) ∈ R if x² + y² = 16

Since x² + y² = 16

So we have

R = { (0,4) , (0, - 4) , (4,0) , ( - 4,0) }

Hence the domain of R = { 0 , - 4 , 4 }

FINAL ANSWER

Hence the correct option is b) { 0, - 4,4 }

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