Question

A relation R is given by the set (x,y) / y=x+3, x e (0,1,2,3,4,5)
determain it's domain and range

Answer 1

According to the Question :

⇒ \dfrac{x \: + \: 1}{x \: + \: 3} \: = \: \dfrac{2}{3}

x+3

x+1

=

3

2

⇒ 3 (x + 1) = 2 (x + 3)

⇒ 3x + 3 = 2x + 6

⇒ 3x - 2x = 6 - 3

⇒ x = 3

The numerator of fraction = 3

• The denominator of a fraction = x + 2

⇒ 3 + 2

⇒ 5

The denominator of a fraction = 5

Fraction = \dfrac{3}{5}

5

3