a relation R on the set A={0,2,3,4,5,6,8,10,12} is defined as R={(x ,y):x, y belongs to A and 3x+ 4y =24} write the elation as a set ordered pairs, also find the domain and range of the relation
Answers
- The relation as a set ordered pairs is R = {(0,6) , (4,3) , (8,0)}
- The domain of the relation R = {0, 4, 8}
- The range of the relation R = {0, 3, 6}
Given :
A relation R on the set A = { 0 , 2 , 3 , 4 , 5 , 6 , 8 , 10 , 12 } is defined as R = {(x,y) : x,y belongs to A and 3x + 4y = 24 }
To find :
- The relation as a set ordered pairs
- The domain of the relation
- The range of the relation
Solution :
Step 1 of 4 :
Write down the given relation
A relation R on the set A = { 0 , 2 , 3 , 4 , 5 , 6 , 8 , 10 , 12 } is defined as
R = {(x,y) : x, y belongs to A and 3x + 4y = 24 }
Step 2 of 4 :
Express the relation as a set ordered pairs
For x = 0 ∈ A we have y = 6 ∈ A
For x = 2 ∈ A we have y = 9/2 ∉ A
For x = 3 ∈ A we have y = 15/4 ∉ A
For x = 4 ∈ A we have y = 3 ∈ A
For x = 5 ∈ A we have y = 9/4 ∈ A
For x = 6 ∈ A we have y = 3/2 ∉ A
For x = 8 ∈ A we have y = 0 ∈ A
For x = 10 ∈ A we have y = - 3/2 ∉ A
For x = 12 ∈ A we have y = - 3 ∉ A
Thus the relation as a set ordered pairs is given by
R = {(0,6) , (4,3) , (8,0)}
Step 3 of 4 :
Find the domain of the relation
The domain of the relation R
= { x ∈ A : (x,y) ∈ R }
= {0, 4, 8}
Step 4 of 4 :
Find the range of the relation
The range of the relation R
= { y ∈ A : (x,y) ∈ R }
= {0, 3, 6}
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In domain and range of a relation, if R be a relation from set A to set B, then
• The set of all first components of the ordered pairs belonging to R is called the domain of R.
Thus, Dom(R) = {a ∈ A: (a, b) ∈ R for some b ∈ B}.
• The set of all second components of the ordered pairs belonging to R is called the range of R.
Thus, range of R = {b ∈ B: (a, b) ∈R for some a ∈ A}.
Therefore, Domain (R) = {a : (a, b) ∈ R} and Range (R) = {b : (a, b) ∈ R}
Note:
The domain of a relation from A to B is a subset of A.
The range of a relation from A to B is a subset of B.