A relief camp has the provision of food for 150 persons for 10 days.
After running the camp for 2 days, 50 more persons were accomodated.
How many more days can the camp provide food for all the persons?
Answers
5 more days
Let us say that a soldier eats 'n' units of food in a day.
Total ration available = 100 soldiers * 10 days * n = 1000n
In 2 days, 100 soldiers would consume = 100n*2 = 200n
Remaining food = 1000n - 200n = 800n
Number of soldiers = 100 + 60 = 160
Amount of food these soldiers will eat in a day = 160n
Number of days the food will last = 800n / 160n = 5 days
Given : A relief camp has the provision of food for 150 persons for 10 days.
After running the camp for 2 days, 50 more persons were accommodated.
To Find : How many more days can the camp provide food for all the persons
Solution:
provision of food for 150 persons for 10 days.
Hence food available = 150 x 10 = 1500 mandays
running the camp for 2 days
Food consumed = 150 x 2 = 300 mandays
Food remaining = 1500 - 300 = 1200 man days
Noe men = 150 + 50 = 200
more days the camp provide food for all the persons = 1200/200
= 6 days
6 more days the camp can provide food for all the persons
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