Math, asked by SatyajitLahiri, 2 months ago

A relief camp has the provision of food for 150 persons for 10 days.

After running the camp for 2 days, 50 more persons were accomodated.

How many more days can the camp provide food for all the persons?​

Answers

Answered by Anonymous
0

5 more days

Let us say that a soldier eats 'n' units of food in a day.

Total ration available = 100 soldiers * 10 days * n = 1000n

In 2 days, 100 soldiers would consume = 100n*2 = 200n

Remaining food = 1000n - 200n = 800n

Number of soldiers = 100 + 60 = 160

Amount of food these soldiers will eat in a day = 160n

Number of days the food will last = 800n / 160n = 5 days

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