Question

A relief camp has the provision of food for 150 persons for 10 days.

After running the camp for 2 days, 50 more persons were accomodated.

How many more days can the camp provide food for all the persons?​

Answer 1

Answer:

5 days

Step-by-step explanation:

Let us say that a soldier eats 'x' units of food in a day.

Total ration available = 100 soldiers * 10 days * x = 1000x

In 2 days, 100 soldiers would consume = 100x*2 = 200x

Remaining food = 1000x - 200x = 800x

Number of soldiers = 100 + 60 = 160

Amount of food these soldiers will eat in

a day = 160x

Number of days the food will last = 800 x / 160x = 5 days

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Answer 2

Answer:

6 days

Step-by-step explanation:

total amount of food =150 ×10 =1500

used amount = 150×2=300

no of days = 1200/200=6days