A relief camp has the provision of food for 150 persons for 10 days.
After running the camp for 2 days, 50 more persons were accomodated.
How many more days can the camp provide food for all the persons?
Answers
Answered by
1
Answer:
5 days
Step-by-step explanation:
Let us say that a soldier eats 'x' units of food in a day.
Total ration available = 100 soldiers * 10 days * x = 1000x
In 2 days, 100 soldiers would consume = 100x*2 = 200x
Remaining food = 1000x - 200x = 800x
Number of soldiers = 100 + 60 = 160
Amount of food these soldiers will eat in
a day = 160x
Number of days the food will last = 800 x / 160x = 5 days
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Answered by
1
Answer:
6 days
Step-by-step explanation:
total amount of food =150 ×10 =1500
used amount = 150×2=300
no of days = 1200/200=6days
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