Question

a repulsive force between two light charge of 1 microcoulomb each volume is 9 into 10 ^ 9 then the distance between these two charges is a) 10-³ b) 10-⁶ c)10-¹² d)10-²​

Answer 1

Answer:

Two like charges are of magnitude Q

1

=1×10

−9

coulomb and Q

2

=9×10

−9

coulomb respectively.

Let the point at which the force is zero be at x metre distance from charge Q

1

So, distance from Q

2

is (1−x) metre.

Force due to Q

1

= Force due to Q

2

x

2

K×1×10

−9

=

(1−x)

2

K×9×10

−9

(1−x)

2

=9x

2

x=

4

1

m.

i.e. 0.25m from the charge 1×10

−9

C.

please brainliest mark