A rescue boat takes 12 hours to row 90 km downstream and 70 km upstream. what is the rate of current if the boat take 9 hours to row 72 km downstream
Answers
The question is incomplete
Complete question as below:
A rescue boat takes 12 hours to row 90 km downstream and 70 km upstream. what is the rate of current if the boat take 9 hours to row 50 km upstream and 72 km downstream?
Answer:
4 km/h
Step-by-step explanation:
Define x and y:
Let x be the speed upstream
Let y be the speed downstream
The boat takes 12 hours to row 90 km downstream and 70 km upstream
90/y + 70/x = 12
The boat takes 9 hours to row 50 km upstream and 72 km downstream
72/y + 50/x = 9
90/y + 70/x = 12 ---------- [ 1 ]
72/y + 50/x = 9 ---------- [ 2 ]
From [ 1 ]:
90/y + 70/x = 12
90x + 70y = 12xy
45x + 35y = 6xy
35y = 6xy - 45x
35y = x(6y - 45)
x = 35y/(6y - 45) ---------- sub into [ 2 ]
72/y + 50/x = 9
72/y + (50 ÷ 35y/(6y - 45) ) = 9
72/y + 50(6y - 45)/35y = 9
72(35) + 50(6y - 45) = 9(35y)
2520 + 300y - 2250 = 315y
315y - 300y = 2520 - 2250
15y = 270
y = 18
Sub y = 18 into equation [ 1 ]:
90/y + 70/x = 12
90/18 + 70/x = 12
5 + 70/x = 12
70/x = 7
7x = 70
x = 10
Find the speed:
Upstream = x = 10 km/h
Downstream = y = 18 km/h
Find the rate of the current:
Speed of the current = 1/2 (downstream - upstream)
Speed of the current = 1/2 (18 - 10) = 4 km/h
Answer: The rate of the current is 4 km/h
We will assume the speed of the boat as B and the Speed of current as C
speed of downstream = (B + C) Km/h
speed of upstream = (B - C) Km/h
We are given,
time = distance /speed
so, time taken in downstream + time taken in upstream = 12 h
90/(B + C) + 70/(B - C) = 12 ----(1)
Time taken in downstream = 9 h
72/(B + C) = 9
B + C = 8 km/h---------(2) , put it in equation (1)
90/8 + 70/(B -C) = 12
45/4 + 70/(B - C) = 12
70/(B - C) = 12 - 45/4 = 3/4
B - C = 280/3 km/h -------(3)
Now we will solve both equations (2) and (3),
2B = 280/3 + 8 => B = 140/3 + 4 = 152/3 km/h
now we will Put B in equation (2) ,
C = 8 - 152/3 = (24-152)/3 = -128/3 km/h
here , negative sign shows that Current is just opposite side of our assumption
So speed of current = -128/3 km/h