A research survey examines that in a Lahore City, 33% students travel by bus, 42% travel by Auto Rickshaw, and 12% use both. The probability that a random student is selected uses neither of them is? *
0.29
0.75
0.37
0.61
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Given:
Percentage of student that use bus = 33%
Percentage of students that use auto rickshaw = 42%
Percentage of students that use both = 12%
To find:
The probability that a selected does not uses any of them.
Solution:
Probability that a student uses bus = 33/100 = 0.33
Probability that a student uses auto rickshaw = 42/100 = 0.42
Probability that he/she uses both = 12/100 = 0.12
Probability that a student either uses bus or auto rickshaw = 0.33 + 0.42 - 0.12 = 0.63
Probability that a student uses neither of them = 1 - 0.63 = 0.37
The required probability is 0.37.
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