A researcher has prepared a sample of 1-bromopropane from 10g of 1-propanol.
purification he had made 12g of product. Which of the following is percentage yield:
A) 60%.
C) 90%
B) 58%
D) 50%
Answers
Answered by
1
Answer:
(A) 60%
Explanation:
10g×12g
=120g
=120/2g
=60%
Similar questions
English,
4 months ago
Accountancy,
4 months ago
English,
8 months ago
Math,
8 months ago
Physics,
1 year ago