A Residence Association is planning to develop a park in the colony. The rectangular park of dimensions 75m × 25m consists a path of uniform width along its boundary in the out side to develop walking habit among the residents of the colony. To beautify the park, 5 square flower beds are made in the park by spending 10% of the total cost of 5 lakh rupees for Rs.2500 per sq m.
1. The expression for finding the area of the path
Answers
Given : The rectangular park of dimensions 75m × 25m consists a path of uniform width along its boundary in the out side to develop walking habit among the residents of the colony.
To find : 1. The expression for finding the area of the path
The cost of constructing a 1m wide path at Rs. 1250 per sq m
Solution:
park of dimensions 75m × 25m
path out side of width x m , all side
Hence outer boundaries 75 + 2x , 25 + 2x
Area of path = ( 75 + 2x) (25 + 2x) - 75 * 25
= 150x + 50x + 4x ² + 75 * 25 - 75 * 25
= 4x² + 200x
The expression for finding the area of the path = 4x² + 200x
1m wide path Hence area of path = 4(1)² + 200(1)
= 204 m²
Rate = 1250 per sq m
Hence cost = 204 * 1250 = 2,55,000
distance travelled by a person if he completes 10 rounds along the inner boundary of the path = 10 * 2 ( 75 + 25) = 2000 m = 2 km
5 square flower beds are made in the park by spending 10% of the total cost of 5 lakh rupees for Rs.2500 per sq m.
Spend = (10/100) 500000 = 50000
5 square flower beds
=> cost on one flower bed =50000/5 = 10000
Rs.2500 per sq m.
Hence area of one flower bed = 10000/2500 = 4 m²
The side of each square flower bed = √4 = 2 m
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