A resistance of 0.05 ohm have a circuit 3 ampere flowing in it . Calculate the potential difference
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V=IR
V=0.05×3
V=0.15volt
V=0.05×3
V=0.15volt
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we know that according to the Ohm's law
V=IR
V= 3×0.05
V=.15
So the potential difference is 0.15
V=IR
V= 3×0.05
V=.15
So the potential difference is 0.15
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