Question

A resistance of 100 ohms and inductance of 0.5 henry are connected is series with a battery of 20 volts . Find the current in a circuit as a function of t.

Answer 1

Given info : A resistance of 100 ohms and inductance of 0.5 henry are connected is series with a battery of 20 volts.

To find : the current in a circuit as a function of time, t , is ..

solution : using formula of current through the circuit, i = $\frac{E}{R}(1-e^{-\frac{Rt}{L}})$

where E is emf of batter, R is resistance of resistor , L is inductance of inductor and i is current through the circuit.

here, E = 20 volts, R = 100 ohm, L = 0.5 H

now, i = $\frac{20}{100}(1-e^{-\frac{100t}{0.5}})$

= $0.2(1-e^{-200t})$ , this is the required current as a function of time.

Answer 2

Step-by-step explanation:

Given info : A resistance of 100 ohms and inductance of 0.5 henry are connected is series with a battery of 20 volts.

To find : the current in a circuit as a function of time, t , is ..

solution : using formula of current through the circuit, i = \frac{E}{R}(1-e^{-\frac{Rt}{L}})RE(1−e−LRt)

where E is emf of batter, R is resistance of resistor , L is inductance of inductor and i is current through the circuit.

here, E = 20 volts, R = 100 ohm, L = 0.5 H

now, i = \frac{20}{100}(1-e^{-\frac{100t}{0.5}})10020(1−e−0.5100t)

= 0.2(1-e^{-200t})0.2(1−e−200t) , this is the required current as a function of time.