Question

a resistance of 1000 ohm and of 2000 ohm are placed in series with 100v supply.what will be the reading on a voltmeter of internal resistance 5000 ohm when placed across the 1000 ohm resistance and the 2000 ohm resistance

Answer 1

Explanation:

Let R be the equivalent resistance of two parallel resistances,

the internal resistance 4000 ohms and 1000 ohms, then

R=4000×1000/4000+1000=800Ω

Total resistance of the circuit=2000+800=2800Ω

Current flown=1002800A

Voltage measured across 1000 ohms resistance

=1002800×800=28.57142857V